A container of just 10cc has 2.69 xx 10^20 gas molecules at 0^@C. What is the pressure exerted?

A container of just 10cc has 2.69 xx 10^20 gas molecules at 0^@C. What

1.	A container of just 10cc has 2.69 xx 10^20 gas molecules at 0^@C. What is the pressure exerted?
Answer» <html><body><p></p>Solution :Number of <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> of the gas = `(2.69 xx 10^20)/(6.022 xx 10^(23)) = <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>.47 xx 10^(-4)` <br/> Pressure (P) exerted by gas <a href="https://interviewquestions.tuteehub.com/tag/molecules-563030" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULES">MOLECULES</a> : <br/> `P = (nRT)/V = (4.47 xx 10^(-4) xx 82.1 xx273)/10 = 1 atm`.</body></html>