A container of just 10cc has 2.69 xx 10^20 gas molecules at 0^@C. What is the pressure exerted?

A container of just 10cc has 2.69 xx 10^20 gas molecules at 0^@C. What

1.	A container of just 10cc has 2.69 xx 10^20 gas molecules at 0^@C. What is the pressure exerted?
Answer» Solution :Number of MOLES of the gas = `(2.69 xx 10^20)/(6.022 xx 10^(23)) = 4.47 xx 10^(-4)` Pressure (P) exerted by gas MOLECULES : `P = (nRT)/V = (4.47 xx 10^(-4) xx 82.1 xx273)/10 = 1 atm`.