1.

A copper sphere of 2 gm has 2 × 1022 atoms. The charge on the nucleus of each atom is 29e. How many fraction of electrons be eliminated to provide a charge of 2μC to the sphere?

Answer»

Charge on each nucleus = 22 eC
∴ Net charge on nucleus of sphere of mass 2 gm
= (22 e) × (2 × 1022C)
= (4.4 × 1023)eC
∴ Total number of electron on sphere
= (4.4 × 1023)
[∵ Sphere is initially uncharged]
∴ Number of electrons in charge of 2 × 10-6)C
= \(\frac{2 \times 10^{-6}}{1.6 \times 10^{-19}}\) = 1.25 × 1013
∴ Fraction of electrons, which is to be removed
= \(\frac{1.25 \times 10^{13}}{4.4 \times 10^{23}}\)
= 2.84 × (102)-11


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