A copper wire is dipped in silver nitrate solution in beaker A and a silver wire is dipped in a solution of copper sulphate kept in beaker B. If the standard electrode potential for Cu^(2+) +2e^(-) rarr Cu " is " +0.34 and for Ag^(+) +e^(-) rarr Agis 0.80 V . Given E^@(Ni^(2+)|Ni)=-0.25V and E^@(Cu^(2+) |Cu) = 0.34 V Predict in which beacker the ions present will get reduced ?

A copper wire is dipped in silver nitrate solution in beaker A and a s

1.	A copper wire is dipped in silver nitrate solution in beaker A and a silver wire is dipped in a solution of copper sulphate kept in beaker B. If the standard electrode potential for Cu^(2+) +2e^(-) rarr Cu " is " +0.34 and for Ag^(+) +e^(-) rarr Agis 0.80 V . Given E^@(Ni^(2+)\|Ni)=-0.25V and E^@(Cu^(2+) \|Cu) = 0.34 V Predict in which beacker the ions present will get reduced ?
Answer» ANSWER :In BEAKER A , `AG^(+)` will be REDUCED.