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A copper wire is dipped in silver nitrate solution in beaker A and a silver wire is dipped in a solution of copper sulphate kept in beaker B. If the standard electrode potential for Cu^(2+) +2e^(-) rarr Cu " is " +0.34 and for Ag^(+) +e^(-) rarr Agis 0.80 V . Given E^@(Ni^(2+)|Ni)=-0.25V and E^@(Cu^(2+) |Cu) = 0.34 V Predict in which beacker the ions present will get reduced ?

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :In <a href="https://interviewquestions.tuteehub.com/tag/beaker-894039" style="font-weight:bold;" target="_blank" title="Click to know more about BEAKER">BEAKER</a> A , `<a href="https://interviewquestions.tuteehub.com/tag/ag-362275" style="font-weight:bold;" target="_blank" title="Click to know more about AG">AG</a>^(+)` will be <a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a>.</body></html>


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