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A cricket ball is thrown at a speed ofms^(-1) in a direction 30^(@) above the horizontal . Calculate (a) the maximum height , (b) the time taken by the ball to return to the same thrower to the point where the ball returns to the same level. |
Answer» <html><body><p></p>Solution :The maximum <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> by <br/> `h_(m)=((v_(0)sintheta_(@))^(2))/(2g)=((28sin30^(@))^(2))/(2(9.8))m`<br/>`=(14xx14)/(2xx9.8)=10.0m`<br/> (b)The time taken to return to the same level is `T_(f)=(2v_(@)sintheta_(@))//<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>=(2xx28xxsin30^(@))//9.8=28//9.8s=2.9s`<br/>(c ) The distance from the thrower to the point where the ball returns to the same level is<br/>`R=((v_(@)^(2)sin2theta_(@)))/(g)=(28xx28xxsin60^(@))/(9.8)=69m`</body></html> | |