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A cricket ball of mass 100g moving at a speed of 20m/s is brought to rest in 3s. Find the average force applied by the player |
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Answer» mass of the ball (m) =100g or 0.1kginitial velocity (U) =25 SM time (t) = 0.025sec.final velocity (v) = 0Initial momentum = mu = 0.1×25 = 2.5 skgm Final momentum = mv (which is equal to 0, since v is zero)CHANGE in momentum = mv-mu = 0 - 2.5 = -2.5 skgm Average force = timeChangeinmomentum = - 0.025(2.5) = -100 skgm = -100 NThe NEGATIVE sign actually shows that the force was applied opposite to the direction of the motion of the ball. So, the average force applied by the player will be 100 |
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