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A cricket ball of mass 100g moving at a speed of 20m/s is brought to rest in 3s. Find the average force applied by the player |
Answer» <html><body><p>mass of the ball (m) =100g or <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>.1kginitial velocity (<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>) =25 <a href="https://interviewquestions.tuteehub.com/tag/sm-631424" style="font-weight:bold;" target="_blank" title="Click to know more about SM">SM</a> time (t) = 0.025sec.final velocity (v) = 0Initial momentum = mu = 0.1×25 = 2.5 skgm Final momentum = mv (which is equal to 0, since v is zero)<a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in momentum = mv-mu = 0 - 2.5 = -2.5 skgm Average force = timeChangeinmomentum = - 0.025(2.5) = -100 skgm = -100 NThe <a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a> sign actually shows that the force was applied opposite to the direction of the motion of the ball. So, the average force applied by the player will be 100</p></body></html> | |