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                                    A cruve is respresented by C=21x^(2)-6xy+29y^(2)+6x-58y-151=0 The lengths of axes are | 
                            
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Answer»   `6,2 sqrt(6)` `2(x-3y+3)^(2)+2(3x+y-1)^(2)=180` or `((x-3y+3)^(2))/(60)+((3x+y-1)^(2))/(90)=1` or `((x-3y+3)/(sqrt(1+3^(2))sqrt(6)))^(2)+((3x+y-1)/(3sqrt(1+3^(2))))=1` Thus, C is an ellipse whose lengths of AXES are `6,2sqrt(6)`. The minor and the major axes are `x-3y+3=0 and 3x+y-1=0`, respectively. Their point of intersection gives the CENTER of the center of the conic. THEREFORE, Center `-=(o,1)`  | 
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