1.

A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8 g cm^(-3), then the number of atoms present in 256 g of the crystal is Nxx10^24 . The value ofN is

Answer»


Solution :`rho=(ZxxM)/(a^3xxN_0xx10^(-30))`where a is in pm and M in g `MOL^(-1)`
`8=(4xxM)/((400)^3xx6xx10^23xx10^(-30))` or M=76.8
MOLES in 256 g =`256/76.8`=3.33
`THEREFORE` No. of atoms =`3.33xx6xx10^23=2xx10^24`


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