A cube of side b has a charge q at each of its vertices. The electric

1.	A cube of side b has a charge q at each of its vertices. The electric field due to this charge distribution at the centre of the cube is(a) \(\frac {q}{b^2}\)(b) \(\frac {q}{2b^2}\) (c) \(\frac {32q}{b^2}\) (d) Zero
Answer» (d) zero Thereis an equal charge at diagonally opposite comer. The fields due the these at the centre cancel out. Therefore, the net field at the centre is zero.

A cube of side b has a charge q at each of its vertices. The electric field due to this charge distribution at the centre of the cube is(a) \(\frac {q}{b^2}\)(b) \(\frac {q}{2b^2}\) (c) \(\frac {32q}{b^2}\) (d) Zero

Answer»

(d) zero

Thereis an equal charge at diagonally opposite comer. The fields due the these at the centre cancel out. Therefore, the net field at the centre is zero.

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A cube of side b has a charge q at each of its vertices. The electric field due to this charge distribution at the centre of the cube is(a) \(\frac {q}{b^2}\)(b) \(\frac {q}{2b^2}\) (c) \(\frac {32q}{b^2}\) (d) Zero

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