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A current carrying wire heats a metal rod. The wire provides a constant power P to the rod. The metal rod is enclosed in an insulated container. It is observed that the temperature (T) in the metal rod change with the (t) as `T(t)=T_(0)(1+betat^(1//4))` where `beta` is a constant with appropriate dimension of temperature. the heat capacity of metal is :A. `(4P(T(t)-T_(0))^(3))/(beta^(4)T_(0)^(4))`B. `(4P(T(t)-T_(0))^(2))/(beta^(4)T_(0)^(3))`C. `(4P(T(t)-T_(0))^(4))/(beta^(4)T_(0)^(5))`D. `(4P(T(t)-T_(0)))/(beta^(4)T_(0)^(2))` |
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Answer» Correct Answer - A dQ=HdT `(dQ)/(dt)=H.(dT)/(dt)` `P=H.T_(0).beta.1/4.t^(-3//4)` `(4P)/(T_(0)beta)=t^(-3//4).H` Now `T-T_(0)=T_(0)betat^(1//4)` So, `t^(3//4) =((T-T_(0))/(T_(0)beta))^(3)` `:. H=(4P(T-T_(0))^(3))/(T_(0)^(4)beta^(4))` |
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