InterviewSolution
Saved Bookmarks
| 1. |
A current loop consists of two identical semicircular parts each of radius R, one lying in the x-y plane and the other in x-y plane. If the current in the loop is i, the resultant magnetic field due to two semicircular parts at their common centre isA. `(mu_(0)i)/(2sqrt(2)R)`B. `(mu_(0)i)/(2R)`C. `(mu_(0)i)/(4R)`D. `(mu_(0)i)/(sqrt(2)R)` |
|
Answer» Correct Answer - A Due to semi-circular loop in `x-y` plane `B_(1)=(mu_(0)i)/(4R)` along `Z`-axis. Due semi-circular loop in `x-z` plane `B_(2)=(mu_(0)i)/(4R)` along `Y`-axis `B_(1)` is `bot^(ar)` to `B_(2)` `B_(R)=sqrt(B_(1)^(2)+B_(2)^(2))=sqrt(2). (mu_(0)i)/(4R)=(mu_(0)i)/(2sqrt(2)R)` |
|