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A current of 3 A is flowing through a wire of length 2 m and cross- sectional area `1mm^(2)`. If wire contains `10^(29) "electrons"//m^(3)`, calculate the average time taken by an electron to cross the length of the wire. |
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Answer» Correct Answer - `3.36 xx 10^(4)s` Here, `I = 2A ,l = 1 m, A = 2 mm^(2) = 2 xx 10^(-6) m^(2)`, `n = 8.5 xx 10^(28) m^(-1)` Driff speed `upsilon_(d) = (I)/(n A e)` `= (2)/((8.5 xx 10^(28)) xx (2 xx 10^(-6)) xx (1.6 xx 10^(-19))` ` = 7.35 xx 10^(-5)ms^(-1)` Time taken, `t = (l)/(upsilon_(d)) = (1)/(7.35 xx 10^(-5)) = 3.36 xx 10^(4)s` |
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