A current of dry air was bubbled through a bulb containing 26.66g of an organic compound in 200g of water, then through a bulb at the same temperature, containing water and finally through a tube containing anhydrous calcium chloride. The loss of mass in bulb containing water was 0.087g and gain in mass of the calcium chloride tube was 2.036g. Calcium the molecular mass of the organic substance.

A current of dry air was bubbled through a bulb containing 26.66g of a

1.	A current of dry air was bubbled through a bulb containing 26.66g of an organic compound in 200g of water, then through a bulb at the same temperature, containing water and finally through a tube containing anhydrous calcium chloride. The loss of mass in bulb containing water was 0.087g and gain in mass of the calcium chloride tube was 2.036g. Calcium the molecular mass of the organic substance.
Answer» Solution :`(p_(0)-p_(s))/(p_(0))=("LOSS in mass of solvent bulb")/("Grain in mass of CaCl"_(2)"TUBE")` `=(0.087)/(2.036)` Let the molecular mass of the organic substance be `m`. ACCORDING to RAOULT's law, `(p_(0)-p_(s))/(p_(0))=(w//m)/((w)/(m)+(W)/(M))` `(0.087)/(2.036)=((26.66)/(m))/((26.66)/(m)+(200)/(18))=(26.66)/(26.66+(200)/(18)m)` `m=53.75`.