A cylinder containe 20 kg of N_(2) gas (M= 28 kg K^(-1) mol^(-1)) at a [ressire pf 5 atm. The mass of hydrogen (M = 28 kg K^(-1) mol^(-1)) at a pressure of 3 atm contained in the same cylinder at same temperature is

A cylinder containe 20 kg of N_(2) gas (M= 28 kg K^(-1) mol^(-1)) at a

1.	A cylinder containe 20 kg of N_(2) gas (M= 28 kg K^(-1) mol^(-1)) at a [ressire pf 5 atm. The mass of hydrogen (M = 28 kg K^(-1) mol^(-1)) at a pressure of 3 atm contained in the same cylinder at same temperature is
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.08 kg<br/>0.86 kg<br/>0.68 kg<br/>1.68 kg</p>Solution : `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>/T=(nR)/p` <br/> V and T for both <a href="https://interviewquestions.tuteehub.com/tag/cases-910165" style="font-weight:bold;" target="_blank" title="Click to know more about CASES">CASES</a> in same. Hence <br/> `(n_(1))/(p_(1))=(n_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(p_(2))or (m_(1))/(p_(1)M_(1))=(m_(2))/(p_(2)M_(2))` <br/> or `""m_(2)(p_(2)M_(2))/(p_(1)M_(1)).m_(1)=((3)(2))/((5)(28)).20=0.86kg`</body></html>