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A Cylinder contains 0.32 g of oxygen. The same volume of an unknown gas 'X' under similar conditions of temperature and pressure weighs 0.26 g. The gas 'X' is known the contain only carbon and hydrogen atoms in the ratio 1 : 1. Identify the gas 'X'.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :No. of moles of oxygen `(O_(2))` <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> in `0.32 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> = ((0.32 g))/(("32 g mol"^(-1)))=0.1` mol <br/> Volume of `O_(2)` corresponding to 0.1 mole = 2.24 L <br/> Volume of unknown gas 'X' = 2.24 L <br/> 2.24 L of unknown gas 'X' weigh = 0.26 g <br/> 22.4 L of unknown gas 'X' weigh `= ((0.26g))/((2.24L))xx(22.4L)=26g` <br/> Since the gas contains only carbon and <a href="https://interviewquestions.tuteehub.com/tag/hydrogen-22331" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGEN">HYDROGEN</a> in the ratio 1 : 1 , its `C_(2)H_(2)` (Acetylene).</body></html>


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