A cylinder contains 68g of ammonia gas at s.t.p. 1. What is the volum

1.	A cylinder contains 68g of ammonia gas at s.t.p. 1. What is the volume occupied by this gas? 2. How many moles of ammonia are present in the cylinder? 3. How many molecules of ammonia are present in the cylinder? [N-14, H-1]
Answer» (1) NH₃ = 14 + 3 = 17 If 17 gm of NH₃ contains 22.4l at S.T.P Then 68 gm of NH₃ contains \(\frac{22.4}{17}\times68\) = 89.60 l. (2) No. of moles = \(\frac{Mass\,in\,gm}{Gram\,molecular\,mass}\) = \(\frac{68}{17}\) = 4 moles. (3) One mole of NH₃ contains = 6.022 x 10²³ molecules ∴ 4 moles of NH₃ contains = 4 x 6.022 x 10²⁴ molecules.

A cylinder contains 68g of ammonia gas at s.t.p. 1. What is the volume occupied by this gas? 2. How many moles of ammonia are present in the cylinder? 3. How many molecules of ammonia are present in the cylinder? [N-14, H-1]

Answer»

(1) NH₃ = 14 + 3 = 17

If 17 gm of NH₃ contains 22.4l at S.T.P

Then 68 gm of NH₃ contains \(\frac{22.4}{17}\times68\) = 89.60 l.

(2) No. of moles = \(\frac{Mass\,in\,gm}{Gram\,molecular\,mass}\)

= \(\frac{68}{17}\) = 4 moles.

(3) One mole of NH₃ contains = 6.022 x 10²³ molecules

∴ 4 moles of NH₃ contains = 4 x 6.022 x 10²⁴ molecules.