a cylinder made of Copper and Aluminium floats in Mercury of density 1

1.	a cylinder made of Copper and Aluminium floats in Mercury of density 13.6 gram per centimetre cube such that 0.26 part of it is below Mercury find the density of the solid
Answer» The density of the solid can be calculated as follows: As per the question, Density of Mercury = ρ(hg) = 13.6 GRAM per CENTIMETER cube Consider V(solid)= Volume of solid cylinder. ∴ Volume of mercury DISPLACED by the solid cylinder = V(hg) = 0.26 V(solid) Now, By Law of Flotation, WEIGHT of solid cylinder = Weight of mercury displaced by the solid cylinder. ⇒ V(solid) * ρ(solid) * G = V(hg) * ρ(hg) * g ⇒ V(solid) * ρ(solid) = 0.26 V(solid) * 13.6 ⇒ ρ(solid) = 0.26 * 13.6 = 3.536 gram per centimeter cube Therefore, the density of solid is 3.536 gram per centimeter cube.

a cylinder made of Copper and Aluminium floats in Mercury of density 13.6 gram per centimetre cube such that 0.26 part of it is below Mercury find the density of the solid

Answer»

The density of the solid can be calculated as follows:

WEIGHT of solid cylinder = Weight of mercury displaced by the solid cylinder.

⇒ V(solid) * ρ(solid) * G = V(hg) * ρ(hg) * g

⇒ V(solid) * ρ(solid) = 0.26 V(solid) * 13.6

⇒ ρ(solid) = 0.26 * 13.6

= 3.536 gram per centimeter cube