A cylinder of fixed capacity `44.8` litres constains helium gas at standard temperature and pressure. What is the amount of heat needed to raise the temperature of the gas in the cylinder by `15^(@)C` ? Given `R=8.31 j mol e^(-1) K^(-1)` . (For monoatomic gas, `C_(v)=3 R//2`)A. 265 JB. `310.10 J`C. `373.95 J`D. `387.97 J`

A cylinder of fixed capacity `44.8` litres constains helium gas at sta

1.	A cylinder of fixed capacity `44.8` litres constains helium gas at standard temperature and pressure. What is the amount of heat needed to raise the temperature of the gas in the cylinder by `15^(@)C` ? Given `R=8.31 j mol e^(-1) K^(-1)` . (For monoatomic gas, `C_(v)=3 R//2`)A. 265 JB. `310.10 J`C. `373.95 J`D. `387.97 J`
Answer» Correct Answer - C Since one mole of any ideal gas at STP occupies a volume of 22.4 litre. Therefore, cylinder of fixed capacity 44.8 litre must contain 2 moles of helium at STP. For helium, `C_(V)=3/2R` (monatomic) `therefore` Heat needed to raise the temperature, Q= number of moles `xx` molar specific heat `xx` raise in temperature `=2xx3/2Rxx15=45R=45xx8.31J=373.95J`

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