InterviewSolution
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InterviewSolution
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(a) Define the following terms: (i) Molarity (ii) Molal elevation constant `(k_(b))` (b) A solution containing 15 g (molar mass=60 g `mol^(-1))` per litre of solution water has the same osmotic pressure (isotonic ) as a solution of glucose (molar mass =180g `mol^(-1))` in water calculate the mass of glucose present in one litre of its solution. |
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Answer» (a)(i) Molarity (M) : Molrity can be defined as no of moles of solute dissolved per liitre of solutiohn lolarity M= vol of solutio (liter moles of solute) (ii) Molal elevation constant (kb) When 1 molal solution is prepared the elevation in boiling point is called as molal boling point elevation constant (b) For isotonic solution `pi_("urea")=("WBRT")/("MB"xxV)=(15 RT)/(60 V)` `pi_("glucose")=("WBRT")/(180V)` `pi_("urea")=pi_("glucose")` `(15"RT")/(60 V)=("WBRT")/(180V)` WB=`(15xx180)/(60)=45g` |
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