A definite amout of gaseous hydrocarbon was burnt with just sufficient of O_(2).The volume of all reactantswas 600ml,after the explosion the volume of the products [CO_(2)(g) and H_(2)O(g) was found to be 700ml under the similar conditions the molecular formula of the compound is .

A definite amout of gaseous hydrocarbon was burnt with just sufficient

1.	A definite amout of gaseous hydrocarbon was burnt with just sufficient of O_(2).The volume of all reactantswas 600ml,after the explosion the volume of the products [CO_(2)(g) and H_(2)O(g) was found to be 700ml under the similar conditions the molecular formula of the compound is .
Answer» `C_(3)H_(8)` `C_(3)H_(6)` `C_(3)H_(4)` `C_(4)H_(10)` Solution :Mass `%` of `O=((60/(98)xx4xx16+(40)/(80)xx3xx16)xx100)/(100) = 63.18%`