A dielectric slab fills the space between the square plates of a parallel-plate capacitor. The side of each plate of the capacitor is `L`. The magnitude of the bound charges on the slab is `75%` of the magnitude of the free charge on the plates. The capacitance is `480muF` and the maximum charge that can be stored on the capacitor is `240epsilon_(0)L^(2)E_("max"),` where `E_("max")` is the breakdown strength of the medium:A. The dielectric constant for the dielectric slab is 4B. Without the dielectric, the capacitance of the capacitor would be `360muF`C. The plate area is `60L^(2)`D. If the dielectric slab is having the same area as that of the capacitor plate but the width is half the separation between plates of capacitor, the capacitance would be `192muF`

A dielectric slab fills the space between the square plates of a paral

1.	A dielectric slab fills the space between the square plates of a parallel-plate capacitor. The side of each plate of the capacitor is `L`. The magnitude of the bound charges on the slab is `75%` of the magnitude of the free charge on the plates. The capacitance is `480muF` and the maximum charge that can be stored on the capacitor is `240epsilon_(0)L^(2)E_("max"),` where `E_("max")` is the breakdown strength of the medium:A. The dielectric constant for the dielectric slab is 4B. Without the dielectric, the capacitance of the capacitor would be `360muF`C. The plate area is `60L^(2)`D. If the dielectric slab is having the same area as that of the capacitor plate but the width is half the separation between plates of capacitor, the capacitance would be `192muF`
Answer» Correct Answer - A::C::D

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