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A discharge tube containing nitrogen gas at 25^(@)C in evacuated till the pressure is 2xx10^(-2) mm. If the volume of discharge tube is 2 litre. Calculate the number of nitrogen molecules still present in the tube (R=0*0821 L "atm mol"^(-1)K^(-1))

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/step-25533" style="font-weight:bold;" target="_blank" title="Click to know more about STEP">STEP</a> : 1 <a href="https://interviewquestions.tuteehub.com/tag/calculation-907729" style="font-weight:bold;" target="_blank" title="Click to know more about CALCULATION">CALCULATION</a> of number of moles of nitrogen. <br/> Here `P=2xx10^(-2) mm =2xx10^(-2) xx(1)/(760) atm` <br/> `V=2L, T=25^(@)C=298*<a href="https://interviewquestions.tuteehub.com/tag/15k-1792953" style="font-weight:bold;" target="_blank" title="Click to know more about 15K">15K</a>` <br/> According to ideal gas equation. <br/> `PV=nRT:. N(PV)/(RT)=2xx10^(-2)(1)/(760)xx(2)/(0*821)xx(1)/(298*15)` <br/> `:.n=2*15xx10^(-6)` <br/> Step: 2 Calculation of number of molecules. <br/> 1 <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a> of nitrogen contains `=6*02xx10^(23)` molecules. <br/> `2*15xx10^(-6)` mol of nitrogen <a href="https://interviewquestions.tuteehub.com/tag/contain-409810" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAIN">CONTAIN</a> `=6*02xx10^(23)xx2*15xx10^(-6)` <br/> `1*29xx10^(18)` molecules</body></html>


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