A dishonest shopkeeper pretends to sell his goods at cost price but us

1.	A dishonest shopkeeper pretends to sell his goods at cost price but uses false weights and gains 11\(\frac{1}{9}\)%, For a weight of 1 kg he uses (a) a weight of 875 gm (b) a weight of 900 gm (c) a weight of 950 gm (d) a weight of 850 gm
Answer» (b) a weight of 900 gm Let the error (difference between 1 kg and false weight) be x gm. Then, \(\frac{X}{(1000-X)}\) x 100 = \(\frac{100}{9}\) \(\Rightarrow\) \(\frac{X}{(1000-X)}\) = \(\frac{1}{9}\) \(\Rightarrow\) 9x = 1000 – x \(\Rightarrow\) 10x = 1000 \(\Rightarrow\) x = 100 \(\therefore\) Weight used = (1000 – 100) gm = 900 gm.

A dishonest shopkeeper pretends to sell his goods at cost price but uses false weights and gains 11\(\frac{1}{9}\)%, For a weight of 1 kg he uses (a) a weight of 875 gm (b) a weight of 900 gm (c) a weight of 950 gm (d) a weight of 850 gm

Answer»

(b) a weight of 900 gm

Let the error (difference between 1 kg and false weight) be x gm. Then,

\(\frac{X}{(1000-X)}\) x 100 = \(\frac{100}{9}\) \(\Rightarrow\) \(\frac{X}{(1000-X)}\) = \(\frac{1}{9}\)

\(\Rightarrow\) 9x = 1000 – x \(\Rightarrow\) 10x = 1000 \(\Rightarrow\) x = 100

\(\therefore\) Weight used = (1000 – 100) gm = 900 gm.