(a) Explain the following terms : (i) Weight percent (ii) Volume percent (iii) Molarity (iv) Normality (b) How much volume of M/2 HCI solution be diluted to obtain 100 cm^3 of a decimolar solution ?

(a) Explain the following terms : (i) Weight percent (ii) Volume perc

1.	(a) Explain the following terms : (i) Weight percent (ii) Volume percent (iii) Molarity (iv) Normality (b) How much volume of M/2 HCI solution be diluted to obtain 100 cm^3 of a decimolar solution ?
Answer» <html><body><p></p>Solution :(ii) The number of gram moles of HCI will remain the same on dilution. <br/> Suppose, `V cm^3` of y `M/2`HCI are required to be <a href="https://interviewquestions.tuteehub.com/tag/diluted-7675406" style="font-weight:bold;" target="_blank" title="Click to know more about DILUTED">DILUTED</a>. <br/> Since, Number of gram moles in a solution `=("Molarity" <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> "Volume in" cm^(3))/1000` <br/> Therefore, the number of gram moles in cone, solution <br/> `=(1/2 xx v)/1000` <br/> <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, `(1/2 xx V)/1000 =(1/10 xx 100)/(1000)` <br/> Which <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> `V = 20 cm^(3)` <br/> Hence, `20 cm^3` of `M/2`HCI should be diluted to `100 cm^3` to obtain a decimolar solution.</body></html>