(a) Explain the following terms : (i) Weight percent (ii) Volume percent (iii) Molarity (iv) Normality (b) How much volume of M/2 HCI solution be diluted to obtain 100 cm^3 of a decimolar solution ?

(a) Explain the following terms : (i) Weight percent (ii) Volume perc

1.	(a) Explain the following terms : (i) Weight percent (ii) Volume percent (iii) Molarity (iv) Normality (b) How much volume of M/2 HCI solution be diluted to obtain 100 cm^3 of a decimolar solution ?
Answer» Solution :(ii) The number of gram moles of HCI will remain the same on dilution. Suppose, `V cm^3` of y `M/2`HCI are required to be DILUTED. Since, Number of gram moles in a solution `=("Molarity" XX "Volume in" cm^(3))/1000` Therefore, the number of gram moles in cone, solution `=(1/2 xx v)/1000` THUS, `(1/2 xx V)/1000 =(1/10 xx 100)/(1000)` Which GIVES `V = 20 cm^(3)` Hence, `20 cm^3` of `M/2`HCI should be diluted to `100 cm^3` to obtain a decimolar solution.