InterviewSolution
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InterviewSolution
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A famous relation in phyics relates the moving mass ` m` to the rest mass `m_(0)` of a particle in terms of its speed `v` and the speed of light `c`.( This relation first arose as a consequence of the special theory of relativity due to Albert Einstein). A body recalls the relation almost correctly but forgets where to put the constant `c` . He writes `m = (m_(0))/((1- V^(2))^(1//2))`. Guess where to put the missing `c`. |
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Answer» According to the principle of homogenity of dimensions , powers of `M,L , T` on either side of the formula must be equal. For this , on `RHS` , the denominator `(1 - v^(2))^(1//2)` should be dimensionless. Therefore, instead of `(1 - v^(2))^(1//2)` , we should write `( 1 - v^(2)// c^(2))^(1//2)`. Hence, the correct formula would be `m = (m_(0))/(( 1 - v ^(2)// c^(2))^(1//2))` |
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