1.

A flask A contains 0.5 mole of oxygen gas. Another flask B contains 0.4 mole of ozone gas Which of the two flasks contains greater number of oxygen atoms.

Answer»

SOLUTION :Flask A: 1 mole of oxygen gas = `6.023xx10^(23)` molecules
`:.`0.5 mole of oxygen gas = `6.023xx1O^(23)xx0.5` molecules
The number of atoms in flask A = `6.023xx10^(23)xx0.5xx2`
= `6.023xx10^(23)` atoms.
Flask B:1 mole of ozone gas = `6.023xx10^(23)` molecules
`:.` 0.4 mole of ozone gas = `6.023 XX 10^(23)xx0.4` molecules
The number of atoms in flask B = `6.023xx10^(23)xx0.4xx3`
= `7.227xx10^(23)` atoms.
`:.` Flask B CONTAINS a great number of oxygen atoms as compared to flask A.


Discussion

No Comment Found