A flask containing 250 mg of air at 27^(@)Cis heated till 25.5% of air by mass is expelled from it. What is the final temperatuer of the flask ?

A flask containing 250 mg of air at 27^(@)Cis heated till 25.5% of air

1.	A flask containing 250 mg of air at 27^(@)Cis heated till 25.5% of air by mass is expelled from it. What is the final temperatuer of the flask ?
Answer» <html><body><p></p>Solution :Let the volume of flask be V. Let <a href="https://interviewquestions.tuteehub.com/tag/final-461168" style="font-weight:bold;" target="_blank" title="Click to know more about FINAL">FINAL</a> temeperature be T(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>). <br/> Mass of air expelled at `T(K)=(250x25)/(100)=62.5mg` <br/> Mass of air contained in flask `=<a href="https://interviewquestions.tuteehub.com/tag/250-297421" style="font-weight:bold;" target="_blank" title="Click to know more about 250">250</a>-62.5=187.5mg` <br/> now, volume of total air (250 mg) at higher temperature <br/> `V_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=(Vxx250)/(187.5)<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>` <br/> Now `(V_(2))/(T)=(V)/(300)` <br/> or `T=(V_(2)xx300)/(V)=(Vxx250xx300)/(187.5xxV)=400K` or `127^(@)C`</body></html>