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A flask is initially filled with pure N_2O_3(g) having pressure 2 bar and following equilibria are established. N_2O_3(g)hArrNO_2(g)+NO(g)""K_(P_1)=2.5bar 2NO_2(g)hArrN_2O_4(g)""K_(P_2)=? If at equilibrium partial pressure of NO(g) was found to be 1.5 bar,then: |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a> parial pressure of `N_2O_3(g)` is 0.5 bar. <br/>Equilibrium partial pressure of `NO_2(g)` is 0.83 bar.<br/>Equilibrium parital pressure of `N_2O_4` is 0.33 bar. <br/>Value of `K_(P_2)` is 0.48 bar</p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>::D</body></html> | |