A flask is initially filled with pure N_2O_3(g) having pressure 2 bar and following equilibria are established. N_2O_3(g)hArrNO_2(g)+NO(g)""K_(P_1)=2.5bar 2NO_2(g)hArrN_2O_4(g)""K_(P_2)=? If at equilibrium partial pressure of NO(g) was found to be 1.5 bar,then:

A flask is initially filled with pure N_2O_3(g) having pressure 2 bar

1.	A flask is initially filled with pure N_2O_3(g) having pressure 2 bar and following equilibria are established. N_2O_3(g)hArrNO_2(g)+NO(g)""K_(P_1)=2.5bar 2NO_2(g)hArrN_2O_4(g)""K_(P_2)=? If at equilibrium partial pressure of NO(g) was found to be 1.5 bar,then:
Answer» EQUILIBRIUM parial pressure of `N_2O_3(g)` is 0.5 bar. Equilibrium partial pressure of `NO_2(g)` is 0.83 bar. Equilibrium parital pressure of `N_2O_4` is 0.33 bar. Value of `K_(P_2)` is 0.48 bar Answer :A::B::C::D