A flask of 1L having NH_(3)(g) at 2.0atm and 200K is connected with another flask of vol 800ml having HCl(g) at 8atm & 200K through tube of negligible volume. The two gases reacts to form NH_(4)Cl(s) with evolution of 43 KJ/mol heat. If heat capacity of at constant volume is 20J/K/mol and neglecting heat capacity of flask and solid, volume of solid formed and its pressure (R = 0.08). The final pressure in the flask is

A flask of 1L having NH_(3)(g) at 2.0atm and 200K is connected with an

1.	A flask of 1L having NH_(3)(g) at 2.0atm and 200K is connected with another flask of vol 800ml having HCl(g) at 8atm & 200K through tube of negligible volume. The two gases reacts to form NH_(4)Cl(s) with evolution of 43 KJ/mol heat. If heat capacity of at constant volume is 20J/K/mol and neglecting heat capacity of flask and solid, volume of solid formed and its pressure (R = 0.08). The final pressure in the flask is
Answer» 5.375KJ 4.375KJ 6.8KJ 6.375J Solution :`NH_(3(g)) + HCl_((g)) rarr NH_(4)Cl_((s)), Delta H = - 43.0KJ` `{:("INITIAL mole", (1 xx 2)/(0.08 xx 200), (8 xx 0.8)/(0.08 xx 200)0,0),(,= 0.125,=0.4,),("FINAL moles",0,0.275,0.125):}` `:.` heat product = `0.125 xx 43 = 5.375 KJ`