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A flask of 1L having NH_(3)(g) at 2.0atm and 200K is connected with another flask of vol 800ml having HCl(g) at 8atm & 200K through tube of negligible volume. The two gases reacts to form NH_(4)Cl(s) with evolution of 43 KJ/mol heat. If heat capacity of at constant volume is 20J/K/mol and neglecting heat capacity of flask and solid, volume of solid formed and its pressure (R = 0.08). The final pressure in the flask is |
Answer» <html><body><p>5.375KJ<br/>4.375KJ<br/>6.8KJ<br/>6.375J</p>Solution :`NH_(3(g)) + HCl_((g)) rarr NH_(4)Cl_((s)), Delta H = - 43.0KJ` <br/> `{:("<a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> mole", (1 xx 2)/(0.08 xx 200), (<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> xx 0.8)/(0.08 xx 200)0,0),(,= 0.125,=0.4,),("<a href="https://interviewquestions.tuteehub.com/tag/final-461168" style="font-weight:bold;" target="_blank" title="Click to know more about FINAL">FINAL</a> moles",0,0.275,0.125):}` <br/> `:.` heat product = `0.125 xx 43 = 5.375 KJ`</body></html> | |