A foolball at 25^(@)C has 0.5 mole air molecules . calculate the internal energy of air in the ball.

A foolball at 25^(@)C has 0.5 mole air molecules . calculate the inter

1.	A foolball at 25^(@)C has 0.5 mole air molecules . calculate the internal energy of air in the ball.
Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/internal-517481" style="font-weight:bold;" target="_blank" title="Click to know more about INTERNAL">INTERNAL</a> energy of ideal <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> `=3/2` NkT. The number of air molecules is given in terms of number of moles so, rewrite the <a href="https://interviewquestions.tuteehub.com/tag/expression-980856" style="font-weight:bold;" target="_blank" title="Click to know more about EXPRESSION">EXPRESSION</a> as follows: <br/> `U=3/2muRT` <br/> Since `Nk=muR. "Here"mu` is number of moles. <br/> Gas <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> `R=8.31 J/("<a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>")K` <br/> Temperature`T=273+27^(@)C=300K` <br/> `U3/2xx0.5xx8.31xx300=1869.75J` <br/>This is approximately equivalent to the kinetic energy of a man of 57 kg runinf with a speed of 8 `ms^(-1)`</body></html>