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(a)for any mutielectron specie, compare the energies of following orbitals. Justify [ External magnetic & electric fields are absent ] Orbitals to be compared 3d_(xy),2s,4p_(x),4p_(y) (b)compare the "average distance " of the following orbital fromthe nucles. Also commemt on their 'chances of closeness to the nucleus'if they have same averge distance"Orbitals to be compared 1s,2s,3s,3p_(x),3d_(xy). |
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Answer» Solution :(a)` 2slt3d_(xy) lt4p_(x)=4p_(y)` justification compare` (N+l)&if(n+l)` same then 'n' (b) Average distance (on the basis of n) ` 1slt2slt3s=3p_(x)=3d_(xy)` CLOSENESS comparison 3S will be more CLOSE as compare to `3p_(x)` as compared to `3d_(xy)` |
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