A force →F=−k(y^i+x^j) (where k is a positive constant) acts on a particle moving in the x−y plane. Starting from the origin, the particle is taken along the positive x−axis to the point (a,0) and then parallel to the y−axis to point (a,a). Then, total work done by the force is

A force →F=−k(y^i+x^j) (where k is a positive constant) acts on a

1.	A force →F=−k(y^i+x^j) (where k is a positive constant) acts on a particle moving in the x−y plane. Starting from the origin, the particle is taken along the positive x−axis to the point (a,0) and then parallel to the y−axis to point (a,a). Then, total work done by the force is
Answer» A force $\to F = - k (y^i + x^j)$ (where $k$ is a positive constant) acts on a particle moving in the $x - y$ plane. Starting from the origin, the particle is taken along the positive $x -$ axis to the point $(a, 0)$ and then parallel to the $y -$ axis to point $(a, a)$ . Then, total work done by the force is

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A force →F=−k(y^i+x^j) (where k is a positive constant) acts on a particle moving in the x−y plane. Starting from the origin, the particle is taken along the positive x−axis to the point (a,0) and then parallel to the y−axis to point (a,a). Then, total work done by the force is

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