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A force of `5N` gives a mass `m_(1)`, an acceleration of `m//s^(2)`, and a mass `m_(2)`, an acceleration of `24 m//s^(2)`. What acceleration would it give if both the masses are tied together? |
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Answer» Here, force `F=5N` For masses `m_(1)`, accelaration, `a_(1)=8 m//s^(2)`. For masses `m_(2)`, accelaration, `a_(2) = 24 m//s^(2)` For combined mass `(m_(1)+m_(2))`, acceleration, `a=?` From `F = m_(1)a_(1)=m_(2)a_(2), m_(1)= F/(a_(1))= 5/8 kg` and `m_(2)= F/(a_(2))= 5/24 kg` Now, `(m_(1)+m_(2))= 5/8+5/24 = (15+5)/24=20/24 = 5/6 kg`, Thus `a = F/(m_(2)+m_(2))= 5/(5//6) = 6 m//s^(2)` |
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