1.

A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n=1 to the state n=4. Immediately after that the electron jumps to n = m state by emitting a photon of wavelength λe. Let the change in momentum of atom due to the absorption and the emission are ΔPa and ΔPe respectively. If λa/λe=1/5, which of the option (s) is/are correct ?[Use hc=1242 eV nm ; 1 nm=10−9 m, h and c are Plank's constant and speed of light, respectively]

Answer»

A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n=1 to the state n=4. Immediately after that the electron jumps to n = m state by emitting a photon of wavelength λe. Let the change in momentum of atom due to the absorption and the emission are ΔPa and ΔPe respectively. If λa/λe=1/5, which of the option (s) is/are correct ?

[Use hc=1242 eV nm ; 1 nm=109 m, h and c are Plank's constant and speed of light, respectively]





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