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(a) From a solid cylinder of height 30 cm and radius 7 cm, a conical cavity of height 24 cm and same radius is hollowed out. Find the total surface area of the remaining solid.(b) Water in a canal, 8 m wide and 6 m deep, is flowing with a speed of 12 km/hour. How much area will it irrigate in one hour, if 0.05 m of standing water is required? |
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Answer» (a) H = 30 cm, r = 7 cm (for cylinder) h = 24 cm (for cone) Total surface area of remaining solid = CSA of cylinder + CSA of cone + base area of cylinder = 2πrH + πrl + πr2 = πr(2H + l + r) = 22/7 x 7 (60 + 25 + 7) = 22 x 92 = 2024 cm2 (b) flow rate = 12km/h time = 1 hour b = 8m h = 6m lbh = LBH lbh = Area x H 12 x 8 x 6 x 1000 = Area x 5/100 ⇒ Area = 12 x 8 x 6 x 20 x 1000 = 11520,000 m2 |
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