1.

(a) From a solid cylinder of height 30 cm and radius 7 cm, a conical cavity of height 24 cm and same radius is hollowed out. Find the total surface area of the remaining solid.(b) Water in a canal, 8 m wide and 6 m deep, is flowing with a speed of 12 km/hour. How much area will it irrigate in one hour, if 0.05 m of standing water is required?

Answer»

(a) H = 30 cm, r = 7 cm (for cylinder)

h = 24 cm (for cone)

Total surface area of remaining solid

= CSA of cylinder  + CSA of cone + base area of cylinder

 = 2πrH + πrl + πr2

 = πr(2H + l + r)

 = 22/7 x 7 (60 + 25 + 7)

 = 22 x 92

 = 2024 cm2

(b)  flow rate = 12km/h

time = 1 hour

b = 8m

h = 6m

lbh = LBH

lbh = Area x H

12 x 8 x 6 x 1000 = Area x 5/100

⇒ Area = 12 x 8 x 6 x 20 x 1000

 = 11520,000 m2



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