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A function whose graph is symmetrical in opposite quadrants isA. `f(x)=e^(x)+e^(-x)`B. `f(x)=log_(e)x`C. `f(x+y)=f(x)+f(y)`D. ` f(x)=cos(x)+sinx`

Answer» Correct Answer - C
We know that the graph of an odd function is symmetrical in opposite quadrants and the function satisfying the equation .
`f(x+y)=f(x)+f(y)` for all ` x , y in R ` has the forumla
`f(x)=xf(1)` for all ` x in R`.
Clearly , it is an odd function . Hence, its graph is symmetrical in opposite quadrants.


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