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A gas absorbs a photon of 355 nm and emit at two wavelengths. If one of the emission is at 680 |
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Answer» 325 nm or `(HC)/(LAMDA) = (hc)/(lamda_(1)) + (hc)/(lamda_(2)) or (1)/(lamda) = (1)/(lamda_(1)) + (1)/(lamda_(2))` But `lamda = 355 nm, lamda_(1) = 680NM,` `:. (1)/(355) = (1)/(680) + (1)/(lamda_(2))` or `(1)/(lamda_(2)) = (1)/(355) - (1)/(680) = (325)/(355 xx 680)` or `lamda_(2) = (355 xx 680)/(325) = 745nm` |
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