InterviewSolution
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InterviewSolution
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A gas at 300 K has pressure `4 xx 10^(-10) N//m^(2)`. IF `k = 1.38 xx 10^(-23) J//K`, the number of `"molecule"// cm^(3)` is of the order ofA. `10^(3)`B. `10^(5)`C. `10^(6)`D. `10^(9)` |
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Answer» Correct Answer - B using, `PV=nRT =nN((R)/(N))T=nNt_(B)T` `(nN)/(V)=(P)/(k_(B)T)=` number of molecules per `m^(3)` `therefore` Number of mulecules `//cm^(3)=(P)/(k_(B)T)xx10^(-6)` `=(4xx10^(-10)xx10^(-6))/(1.38xx10^(-23)xx300)=10^(5)` |
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