A gas bulb containing air is connected to an open limb manometer at 27^(@) C and at 750 mm Hg . Assuming that intially the level of Hg in the both limbs were same . The bulb was heated to 77^(@)C , what will be differences in the levels of Hg in two limbs ? (Assuming the volume difference of the gas produced is negligible at higher temperature) .

A gas bulb containing air is connected to an open limb manometer at 27

1.	A gas bulb containing air is connected to an open limb manometer at 27^(@) C and at 750 mm Hg . Assuming that intially the level of Hg in the both limbs were same . The bulb was heated to 77^(@)C , what will be differences in the levels of Hg in two limbs ? (Assuming the volume difference of the gas produced is negligible at higher temperature) .
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>7.5 cm Hg <br/>8 cm Hg <br/>6 cm Hg <br/>12.5 cm Hg </p>Solution :`because (P_(1))/(T_(1)) = (P_(2))/(T_(2)) , (<a href="https://interviewquestions.tuteehub.com/tag/750-335306" style="font-weight:bold;" target="_blank" title="Click to know more about 750">750</a>)/(300) = (P_(2))/(350)` <br/> `therefore P_2 = 875` mm Hg <br/> `therefore` So , difference in height= `875 - 750 = <a href="https://interviewquestions.tuteehub.com/tag/125-271180" style="font-weight:bold;" target="_blank" title="Click to know more about 125">125</a>` mm <br/> Hg = 12.5 cm of Hg</body></html>