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A gas cylinder can hold 1 kg of hydrogen at room temperature and pressure:(i) Find the number of moles of hydrogen present.(ii) What weight of CO2 can the cylinder hold under similar conditions of temperature and pressure? (H= 1, C = 12,O -16)(iii) If the number of molecules of hydrogen in the cylinder is X, calculate the number of CO2 molecules in the cylinder under the same conditions of temperature and pressure.(iv) State the law that helped you to arrive at the above result. |
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Answer» (i) Weight of hydrogen = 2 × 1 g = 2 g 2 g of hydrogen corresponds to 1 mole of hydrogen 1 g of hydrogen corresponds to mole of hydrogen 1000 g of hydrogen corresponds to × 1000 g mole of H2 = 500 moles (ii) 1 mole of H2 occupy 22.4 L 500 mole of H2 occupy = 22.4 x 500 By Avogadro’s law the volume occupied by CO2 will be same Weight of CO2 = 12 + 2 x 16 = 44 g 22.4 L will weigh 44 1L will weigh \(\frac{4}{22.4}\) 22.4 x 500L will weigh \(\frac{44}{22.4}\times22.4\times500\) = 22000g = 22kg (iii) X (Because of Avogadro’s law) (iv) Avogadro’s law |
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