1.

A gas is allowe to expandin a well insulated container againsta constant external pressure of2.5 atmfrom an initial volume of2.50 Lto a final volume of 4.50L. The change in internal energy DeltaU of thegas in Joules will be

Answer»

<P>1136.25J`
`-500J`
`-505J`
`+505J`

SOLUTION :`DeltaU =q+w`
For well insulated CONTAINER, process is adiabatic , `q=0`
`:. DeltaU =w= - P DeltaV`
`= - 2.5 atm ( 4.5 - 2.5) L`
`=- 5L atm`
`= 5xx 101.3 J= - 506.5 J `
`= -505J`


Discussion

No Comment Found