1.

A gas is filled in a container at pressure `P_(0)`. If the mass of molecules is halved and their rms speed is doubled, then the resultant pressure would beA. `2P_(0)`B. `4P_(0)`C. `(P_(0))/(4)`D. `(P_(0))/(2)`

Answer» Correct Answer - A
Using, `P=1/3rhov_(rms)^(2)=1/3(mN)/(V)v_(rms)^(2)`
`thereforePpropmv_(rms)^(2)`
As m is halved and `v_(rms)` is doubled then P becomes twice or `2P_(0).`


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