A gas obeys P(V-b) = RT. Then which of the following are correct

1.	A gas obeys P(V-b) = RT. Then which of the following are correct
Answer» <html><body><p>Isochoric curves have the slope = R/V-<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a><br/>Isobaric curves have the slope =R/P with <a href="https://interviewquestions.tuteehub.com/tag/intercept-1047794" style="font-weight:bold;" target="_blank" title="Click to know more about INTERCEPT">INTERCEPT</a> = b<br/>For the gas compressibility factor = 1+ Pb/RT<br/>Attractive forces predominate <a href="https://interviewquestions.tuteehub.com/tag/repulsive-613883" style="font-weight:bold;" target="_blank" title="Click to know more about REPULSIVE">REPULSIVE</a> forces<br/></p>Solution :a) Isochoric = V constant <br/> `P(V- b) = RT , P = ((R )/(V-b))^(T)` , slope = `R/(V-b)` <br/> b) Isobaric = P constant <br/>`(Vb) = (R/P)^T , V = (R/P)^T + b` <br/>slope= `R/P`, constant = b <br/> c) `P (V- b) = RT, PV e= RT + Pb` <br/> `(PV)/(RT) =1+ (b/(RT))P` <br/> ` Z > 1` = repulsive forces dominate.</body></html>

Discussion