A gas occupies 300.0 mL at 27^@C and 730 mm pressure. What would be its volume at standard temperature and pressure (S.T.P.) ?

A gas occupies 300.0 mL at 27^@C and 730 mm pressure. What would be it

1.	A gas occupies 300.0 mL at 27^@C and 730 mm pressure. What would be its volume at standard temperature and pressure (S.T.P.) ?
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :According to the gas equation, `(P_1V_1)/T_1 = (P_2V_2)/T_2` <br/> In the present case, <br/> `P_1 = 730 " mm <a href="https://interviewquestions.tuteehub.com/tag/hg-485049" style="font-weight:bold;" target="_blank" title="Click to know more about HG">HG</a>, " V_1 = 300.0 mL`, <br/>`T_1 = 27 + 273 = 300 K` <br/> `P_2 = 760 " mm Hg, " V_2 = ?, T_2 = 273 K` (at S.T.P.) <br/> <a href="https://interviewquestions.tuteehub.com/tag/substituting-1231652" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTITUTING">SUBSTITUTING</a> the <a href="https://interviewquestions.tuteehub.com/tag/values-25920" style="font-weight:bold;" target="_blank" title="Click to know more about VALUES">VALUES</a>, we have <br/> `(730 xx 300.0)/300 = (760 xxV_2)/273` <br/> `:. "" V_2 = 262.2 mL`.</body></html>