A gas occupies 300.0 mL at 27^@C and 730 mm pressure. What would be its volume at standard temperature and pressure (S.T.P.) ?

A gas occupies 300.0 mL at 27^@C and 730 mm pressure. What would be it

1.	A gas occupies 300.0 mL at 27^@C and 730 mm pressure. What would be its volume at standard temperature and pressure (S.T.P.) ?
Answer» SOLUTION :According to the gas equation, `(P_1V_1)/T_1 = (P_2V_2)/T_2` In the present case, `P_1 = 730 " mm HG, " V_1 = 300.0 mL`, `T_1 = 27 + 273 = 300 K` `P_2 = 760 " mm Hg, " V_2 = ?, T_2 = 273 K` (at S.T.P.) SUBSTITUTING the VALUES, we have `(730 xx 300.0)/300 = (760 xxV_2)/273` `:. "" V_2 = 262.2 mL`.