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A gas of molecular mass 71 g mol^(-1) is enclosed in a vessel at a temperature of 30^@C. If the pressure exerted by the gas is 1065 mm of Hg, calculate the density of the gas. |
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Answer» Solution :GIVEN that, `P = 1065 mm = (1065)/(760)= 1.4` atm `T=30^@C = 30 + 273 = 303 K, M = 71 g mol^(-1)` and `R=0.0821 L " atm " K^(-1) mol^(-1)`. `:."" d=(MP)/(RT)` `:. "" d=(71 xx 1.4)/(0.0821 xx 303) = 4.0 g L^(-1)` HENCE, the DENSITY of the given gas under given conditions is 4.0 grams per litre. |
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