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A gas of molecular mass 71 g mol^(-1) is enclosed in a vessel at a temperature of 30^@C. If the pressure exerted by the gas is 1065 mm of Hg, calculate the density of the gas.

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> that, `P = 1065 mm = (1065)/(760)= 1.4` atm <br/>`T=30^@C = 30 + 273 = 303 K, M = <a href="https://interviewquestions.tuteehub.com/tag/71-334184" style="font-weight:bold;" target="_blank" title="Click to know more about 71">71</a> g mol^(-1)` <br/>and `R=0.0821 L " atm " K^(-1) mol^(-1)`. <br/> `:."" d=(MP)/(RT)`<br/> `:. "" d=(71 xx 1.4)/(0.0821 xx 303) = 4.0 g L^(-1)` <br/><a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, the <a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> of the given gas under given conditions is 4.0 grams per litre.</body></html>


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