A gas under constant pressure of 4.5 xx 10^(5) Pa when subjected to 800 kJ of heat, changes the volume from 0.5 m^(3) to 2.0 m^(3). The change in internal energy of the gas is

A gas under constant pressure of 4.5 xx 10^(5) Pa when subjected to 80

1.	A gas under constant pressure of 4.5 xx 10^(5) Pa when subjected to 800 kJ of heat, changes the volume from 0.5 m^(3) to 2.0 m^(3). The change in internal energy of the gas is
Answer» <html><body><p>`6.75 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(5) J`<br/>`5.25 xx 10^(5) J`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>.25 xx 10^(5) j`<br/>`1.25 xx 10^(5) J`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Here, `P = 4.5 xx 10^(5) Pa, <a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> = 800 kJ, V_(1) = 0.5 m^(3), V_(2) = 2m^(3)` <br/> The work done by the gas is <br/> `Delta W = P Delta V = P(V_(2) - V_(1)) = 4.5 xx 10^(5) (2-0.5) = 6.75 xx 10^(5) J` <br/> From the first law of thermodynamics, the change in internal energy is <br/> `Delta U = Delta Q - Delta W = 800 xx 10^(3) - 6.75 xx 10^(5) = 1.25 xx 10^(5)J`</body></html>