A gas X,Y, at 35^@C has RMS speed 12ms^(-1). On heating the gas twice to the original absolute temperature, the dimer totally dissociated to give monomer. What is the RMS speed of XY_2 molecules at the given elevated temperature?

A gas X,Y, at 35^@C has RMS speed 12ms^(-1). On heating the gas twice

1.	A gas X,Y, at 35^@C has RMS speed 12ms^(-1). On heating the gas twice to the original absolute temperature, the dimer totally dissociated to give monomer. What is the RMS speed of XY_2 molecules at the given elevated temperature?
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :RMS velocity of (C) is given as <br/> `C= sqrt((3RT)/(M))` <br/> Given temperature `T_1= 308K ` <br/> Elevated temperature `T_2= 616K` <br/> ` C_1= sqrt((3RT_1)/(M_1)) andC_2= sqrt((3RT_2)/(M_2))` <br/> The ratio of RMS <a href="https://interviewquestions.tuteehub.com/tag/velocities-1444510" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITIES">VELOCITIES</a> <br/> ` (C_2)/(C_1) = sqrt((T_2)/(T_1) (M_1)/(M_2))= sqrt((<a href="https://interviewquestions.tuteehub.com/tag/161-277444" style="font-weight:bold;" target="_blank" title="Click to know more about 161">161</a> )/( 308) xx ( 2M_2)/(M_2))=2`<br/> RMS speed of `XY_2`molecules = `C_2` <br/> `2 xx C_1= 2 xx 12 = 24ms^(-1)`</body></html>