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A gaseous compound X contained 44.4 %C, 51.9 % N and 3.7% H . Under like conditions 30 cm^(3) of X diffused through a pinhole in 25 sec and the same volume of H_(2) diffused in 4.81 sec . The molecular formula ofX is

Answer» <html><body><p>`C_(2) H_(2) N`<br/>`C_(2) H_4 N_2`<br/>`C_2 H_2 N_2`<br/>`C_4 H_2 N_2`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> of number of atoms in the molecule = Ratio of gram atoms of elements in he <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a> <br/> `<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> : N : H= (44.4)/(12) : (51.9)/(14) : (3.7)/(1)` <br/> `= 3.7 : 3.7 : 3.7 = 1 : 1 :1 ` <br/> `therefore ` empirical <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> of `X = CNH`<br/> Ratio of <a href="https://interviewquestions.tuteehub.com/tag/rate-1177476" style="font-weight:bold;" target="_blank" title="Click to know more about RATE">RATE</a> of diffusion of X and that of `H_(2)` is given by <br/> `(r_(x))/(r_(H_(2))) = (30 xx 4.81 )/(25 xx 30) = sqrt((2)/(M))` <br/> On solving , M = 54 <br/> `therefore` molecular formula of x is `C_(2) H_(2) N_(2)`</body></html>


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