A gaseous hydrocarbon consumed 5 times its volume of oxygen as for combustion. The volume of CO_(2) produced in the reaction is thrice the volume of hydrocarbon under the same conditions What is the ratio of molecular weight to emperical formula weight of the hydrocarbon?

A gaseous hydrocarbon consumed 5 times its volume of oxygen as for com

1.	A gaseous hydrocarbon consumed 5 times its volume of oxygen as for combustion. The volume of CO_(2) produced in the reaction is thrice the volume of hydrocarbon under the same conditions What is the ratio of molecular weight to emperical formula weight of the hydrocarbon?
Answer» <html><body><p>1<br/>2<br/>3<br/>4</p>Solution :`C_(2)H_(2):(<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a>)/(26)xx100=92.3, C_(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)H_(6):(72)/(<a href="https://interviewquestions.tuteehub.com/tag/78-335791" style="font-weight:bold;" target="_blank" title="Click to know more about 78">78</a>)xx100=92.3`</body></html>