A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of CO_(2). The empirical formula of the hydrocarbon is

A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g

1.	A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of CO_(2). The empirical formula of the hydrocarbon is
Answer» `C_(7)H_(8)` `C_(2)H_(4)` `C_(3)H_(4)` `C_(6)H_(5)` Solution :Let the mass of GASEOUS HYDROCARBON taken = w gm `:. %C = (12)/(44) xx (3.08)/(w)xx 100 = (84)/(w)` `%H = (2)/(18)xx (0.72)/(w)xx 100 = (8)/(w)` Ratio of C : H atoms `= (84)/(w) xx(1)/(12) : (8)/(w) xx (1)/(1) = 7 : 8` THUS, E.F. = `C_(7)H_(8)`.