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A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of `CO_(2)`. The empirical formula of the hydrocarbon isA. `C_(7)H_(8)`B. `C_(2)H_(4)`C. `C_(3)H_(4)`D. `C_(6)H_(5)` |
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Answer» Correct Answer - A Let the mass of gaseous hydrocarbon taken = w gm `:. %C = (12)/(44) xx (3.08)/(w) xx 100 = (84)/(w)` `%H = (2)/(18) xx (0.72)/(w) xx 100 = (8)/(w)` Ratio of C : H atoms `= (84)/(w) xx(1)/(12) : (8)/(w) xx (1)/(1) = 7 : 8` Thus, E.F. = `C_(7)H_(8)`. |
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